Number System Problems and Solutions | Aptitude Questions and Answers

Number System

Formula

$1+2+3+...+n=\frac{n(n+1)}{2}$

$1^2+2^2+3^2+...+n^2 = \frac{n(n+1)(2n+1)}{6}$

$1^3+2^3+3^3+...+ n^3=\left [ \frac{n(n+1)}{2} \right ]^2$

Arithmetic Progression (கூட்டுத்தொடர்)

Formula

$t_{n} = a + (n-1)d$

$n=\left [ \frac{l-a}{d} \right ]+ 1$

$s_{n}= \frac{n}{2}\left [ 2a+(n-1)d) \right ]$

$s_{n}=\frac{n}{2}\left [ a+l \right ]$

Geometric Progression (பெருக்குத்தொடர்)

Formula

$t_{n} = ar^{n-1}$

$n=ar^{n-1}$

$s_{n} =\frac{a(r^{n}-1)}{r-1}$

Number System Problems and Solutions

Total – 11 Parts

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